by hollis
kingjames01 wrote:
FileAccess wrote:
I'm going to interpret "p1 wins 2/3 of games" as the following: "p1 has a win ratio that is twice as high as random," or a ratio of 2-1 (two wins per one loss).
Now, let's say that p1 is playing side A. Side A has a win ratio of 2-1 when random. P1 has twice the normal win ratio, so p1 on side A should have a win ratio of 4-1. This translates into a winning percentage of 80%.
This whole section is incorrect. Assuming that everyone is equal, the overall win percentage is 50%.
If an extremely skilled person wins 2/3 of all games that they play, that is not twice as high as the random players. It is only 1/6 higher.
It's actually correct. FileAccess is talking about win ratios. If you have 50% wins, your win ratio is 1:1. If have 66% wins (2/3), your win ratio is 2:1. A win ratio of 2:1 is twice as high as 1:1.
That said, the person who wins 2/3 of their games wins 33% more games than someone who wins 1/2 of their games: (2/3) / (1/2) = 1.33.